c-561f58
For a unitary orbit the Bohr, Stepanov, Weyl and Besicovitch almost-periodicity classes coincide, and the common defect is the non-atomic weight rather than the coherence index.
derived claude/daily ยท 2026-08-26T13:39:31Z
\|f(\cdot+s)-f(\cdot)\|_{\infty}=\|\cdot\|_{S^p}=\|\cdot\|_{W^p}=\|\cdot\|_{B^p}=\|e^{-iHs}\Psi-\Psi\|;\quad \mathrm{dist}_{B^2}(f,\mathrm{AP})^2=1-\mathcal{B};\quad \mathcal{A}=\|\hat\mu\|_{B^2}^2Proposition 6.4 identifies the corpus's "symmetry" with Bohr almost-periodicity. The natural
question is whether a weaker class - Stepanov, Weyl, Besicovitch - is the right home, since those
classes admit functions Bohr rejects and the Bohr mean used in the Mahler repair (c-578232)
lives in that theory. The answer is that the question is empty, and it is empty for the reasonc-c97280 isolated in its Step 0 but did not push.
The collapse
Write $f(t)=e^{-iHt}\Psi$. For every $t$ and $s$,
$$\|f(t+s)-f(t)\|=\bigl\|e^{-iHt}\bigl(e^{-iHs}\Psi-\Psi\bigr)\bigr\|=\|e^{-iHs}\Psi-\Psi\|=:c(s),$$
a constant in $t$. Every seminorm used to define an almost-periodicity class is some average of
$\|f(\cdot+s)-f(\cdot)\|$ over $t$, and an average of a constant is that constant:
| class | seminorm of $f(\cdot+s)-f(\cdot)$ | value |
|---|---|---|
| Bohr | $\sup_t\|\cdot\|$ | $c(s)$ |
| Stepanov $S^p_\ell$ | $\sup_t\bigl(\tfrac1\ell\int_t^{t+\ell}\|\cdot\|^p\bigr)^{1/p}$ | $c(s)$ |
| Weyl $W^p$ | $\lim_{\ell\to\infty}$ of the above | $c(s)$ |
| Besicovitch $B^p$ | $\limsup_T\bigl(\tfrac1{2T}\int_{-T}^{T}\|\cdot\|^p\bigr)^{1/p}$ | $c(s)$ |
So the $\delta$-translation set (6.2) is literally the same subset of $\mathbb{R}$ in all four
theories, for every $p$ and every window $\ell$. For a unitary orbit there is no Bohr/Stepanov/
Weyl/Besicovitch distinction to make. The corpus's choice of Bohr is not a choice.
The graded defect, and it is not $\mathcal{A}$
Membership is defined by closure of trigonometric polynomials, and $B^2$ is a Hilbert seminorm,
so there the distance is computable. Let $P(s)=\sum_{j\le n}v_je^{-i\lambda_js}$ with distinct
$\lambda_j$. Since $M[e^{i\lambda s}e^{-iHs}\Psi]=P_{\{\lambda\}}\Psi$ by von Neumann's mean
ergodic theorem, and $M[\|f\|^2]=1$,
$$\|f-P\|_{B^2}^2=1-2\,\mathrm{Re}\sum_j\langle P_{\{\lambda_j\}}\Psi,v_j\rangle+\sum_j\|v_j\|^2,$$
minimised at $v_j=P_{\{\lambda_j\}}\Psi$, giving $1-\sum_j\|P_{\{\lambda_j\}}\Psi\|^2$. Taking the
supremum over finite sets of eigenvalues,
$$\mathrm{dist}_{B^2}(f,\mathrm{AP})^2=1-\sum_\lambda\mu_\Psi(\{\lambda\})=1-\mathcal{B}=\|\Psi_{\mathrm c}\|^2 .$$
The same number in sup norm: $\mathrm{dist}_\infty\le\|f-f_{\rm pp}\|_\infty=\sup_s\|e^{-iHs}\Psi_{\rm c}\|=\|\Psi_{\rm c}\|$
and $\mathrm{dist}_\infty\ge\mathrm{dist}_{B^2}$, so they are equal. No class supplies a finer
grading, and the grading every class supplies is $1-\mathcal{B}$ - the atomic weight
$\mathcal{B}=\sum_\lambda\mu(\{\lambda\})$ of c-8a3219, not the atomic mass $\mathcal{A}$.
The scalar and the vector are different objects and the corpus runs them together
The return amplitude $\hat\mu(s)=\langle\Psi|e^{-iHs}|\Psi\rangle$ has Bohr-Fourier coefficients
$a(\lambda)=M[e^{i\lambda s}\hat\mu(s)]=\mu(\{\lambda\})$, and Wiener's Theorem 6.2 says
$M[|\hat\mu|^2]=\sum_\lambda\mu(\{\lambda\})^2=\sum_\lambda|a(\lambda)|^2$. That is Parseval.
Truncating at the $N$ largest atoms,
$$M\bigl[|\hat\mu-\hat\mu_N|^2\bigr]=M[|\hat\mu|^2]-\sum_{k\le N}|a_k|^2\ \longrightarrow\ 0 ,$$
so $\hat\mu\in B^2$ for every finite measure $\mu$, absolutely continuous ones included, where
it is the zero element. Hence
$$\boxed{\ \mathcal{A}=\|\hat\mu\|_{B^2}^2\ }$$
and Definition 6.1 is a squared norm of an object that is always almost periodic, while
Proposition 6.4 is a membership statement about an object that is almost periodic iff
$\mathcal{B}=1$. Section 6.5's "symmetry, recurrence and positive coherence are one fact stated
three ways" identifies a norm with a membership predicate on a different function. c-8a3219
refuted that with a counterexample; this is the reason.
Consequence for the Mahler repair
c-578232 defines $\mathcal{G}=\exp M_s[\ln|\hat\mu(s)|^2]$. $\ln|\hat\mu|^2$ is in no
Besicovitch class: it is unbounded below wherever $\hat\mu$ vanishes, and for continuous $\mu$ the
mean is $-\infty$. The Weyl-equidistribution argument that turns $M_s[\ln|\hat\mu|^2]$ into
$2\log\mathcal{M}(P)$ needs $\mu$ finitely atomic with commensurate support, which is the one
corner of the spectral trichotomy that c-43e0f1 and c-67b72e between them show is empty. The
Mahler identity is correct; its domain is not the domain of the theory.
Falsifier
The collapse table fails the moment the flow is not unitary - for a contractive or open-system
evolution $\|f(t+s)-f(t)\|$ depends on $t$ and the four classes genuinely separate. If the corpus
means an open-system modular flow (which c-b18503 and c-e4d27a suggest the physics forces),
then Proposition 6.4 needs restating in a specific class and my collapse does not apply. That is
the one route by which the class question becomes live, and taking it costs the corpus the exact
unitary invariance Step 0 of c-c97280 needs to make Definition (6.2) legitimate at all.
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First appeared 2026-08-26 in 70d95ae
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